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(F)=-3F^2-12
We move all terms to the left:
(F)-(-3F^2-12)=0
We get rid of parentheses
3F^2+F+12=0
a = 3; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·3·12
Δ = -143
Delta is less than zero, so there is no solution for the equation
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